decorative solar panels
The energy required to help light output of the solar system?
A solar power garden light, lighting for roads or the provision of decorative lighting. The solar panel on top of the device of charging a nickel-cadmium AA size during the day. When night falls, the fall in the level of light is recorded by the solar panel and LED in the bottom of the device is illuminated. The internal battery provides an emf of 1.2 V, and the LED draws a current of 25 mA when lit. Estimation of daily energy requirements of the screen if it is designed to operate up to 12 hours at night? Please show work outside so I can learn to do this in use in the future, thanks in advance!
One thing you have to do the right away is the P <> E * R for energy. However, it is related. Step One ======== Find the power. P = E * I = P?? E = 1.2 V I = 25 mA = 25 mA * [1 amp / 1000 m] = 0.025 amps P = 1.2 * 0,025 = 3 * 10 ^ -2 watts or 0.03 watts. Step Two: Find ======= the power P T * t = energy = 12 hours = 12 hours [3.600 seconds / 1 hour] = 43,200 seconds. Power = 0.03 * 43 200 = 1296 J, which is a lot of energy. The good thing is solar. Edit ==== Do you have a variety of responses. From 3 major contributors or less. I can do a lot of errors so mine would look very carefully. But I think I have reason. Usually, one of the other two are correct – much more often than I am.